Advanced Placement (AP), 12.11.2020 18:00 Incrouyable

What are some of the factors that might have facilitated Chinggis Khan's conquest of the East?

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The arrogance of the orasmian sultan Ala ad-Din Muhammad II The Sultan's escape from the city of Bukhara, leaving her unprotected. The Mongols' will for revenge The fear that other cities in the Middle East had of the Mongols.

Explanation:

The Mongols were interested in establishing peaceful relations with the cities of the Middle East and for this reason, Genghis Khan sent traders and diplomats to the city of Bukhara, so that business relations could be developed that would be beneficial for both cities. However, the sultan Ala ad-Din Muhammad II, used his arrogance to present himself stronger and more influential than the Mongols and arrested all the people sent by Genghis Khan, besides killing and disfiguring some, claiming that they were spies.

This sparked the ire of the Mongols who, driven by the thirst for vengeance, went to the city, along with Genghis Khan, in order to conquer it. The sultan, in fear, fled and left the city completely unprotected, making it easier for Genghis Khan to show all his military power and take over the city, in addition to invading other cities in the Middle East. In addition, many cities fearfully surrendered to Mongolian domination, which made it easier for Mongolians to dominate the Middle East.

Answer from: Quest

The answer is (d) 7/2======we have $f(x) = \begin{cases} x & \text{ for } x \le 0 \\ x + 1 & \text{ for } x \ \textgreater \ 0 \end{cases}$ we also have an integral $\displaystyle\int_{-2}^1 x\, f(x)\; dx$ notice how function f splits up at x = 0. there's a left piece and a right pieceso we'll need to do the same thing with our integral: split it at x = 0we use a property of integrals that allows us to split up and sum: $\displaystyle\int_{-2}^1 x\, f(x)\; dx = \displaystyle\int_{-2}^0 x\, f(x)\; dx + \displaystyle\int_{0}^1 x\, f(x)\; dx$ notice that for the piecewise function f, the function has the equationf(x) = x when x ≤ 0. so for the integral $\int_{-2}^0 x\, f(x)\; dx$ , f(x) = x so it changes into $\begin{aligned} \int_{-2}^0 x\, f(x)\; dx & = \int_{-2}^0 x \cdot x\; dx \\ & = \int_{-2}^0 x^2\; dx \\ & = \left[\frac{x^3}{3}\right]_{-2}^0 & & \text{\footnotesize antidifferentiate} \\ & = 0 - \frac{(-2)^3}{3} \\ & = \frac{8}{3} \end{aligned}$ for the piecewise function f, the function has the equationf(x) = x+1 when x > 0. for the integral $\int_{0}^1 x\, f(x)\; dx$ , we have $\begin{aligned} \int_{0}^1 x\, f(x)\; dx & = \int_{0}^1 x(x+1)\; dx \\ & = \int_{0}^1 (x^2+x)\; dx \\ & = \left[ \frac{x^3}{3} + \frac{x^2}{2}\right]_0^1 \\ & = \frac{1}{3} + \frac{1}{2} - 0 = \frac{5}{6} \end{aligned}$ therefore, back to our splitted integral: $\begin{aligned} \displaystyle\int_{-2}^1 x\, f(x)\; dx & = \displaystyle\int_{-2}^0 x\, f(x)\; dx + \displaystyle\int_{0}^1 x\, f(x)\; dx \\ & = \frac{8}{3} + \frac{5}{6} \\ & = \frac{7}{2} \end{aligned}$
Can anyone me on this ap calc question? ?

Can anyone me on this ap calc question? ?

Answer from: Quest

Answerhis desire for money

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