A flock of geese is approaching a photographer, flying information. The photographer starts taking photographs when the lead goose is 300 feet horizontally from her and continues taking photographs until it is 100 feet past. The flock is flying a steady 30 feet per second. Write and solve an equation to find the times after the photographing begins that the lead goose is at a horizontal distance of 75 feet from photographer.

Answerin vivo exposure;

I'm not sure but it could be c ( not a 100% sure )

The answer is    (d) 7/2======we have    we also  have an integral      notice how function f splits up at x = 0. there's a left piece and a right pieceso we'll need to do the same thing with our integral: split it at x = 0we use a property of integrals that allows us to split up and sum:     notice that for the piecewise function f, the function has the equationf(x) = x when x  ≤ 0. so for the integral  , f(x) = x so it changes into      for the piecewise function f, the function has the equationf(x) = x+1  when x  > 0. for the integral  , we have    therefore, back to our splitted integral:    

(the column on the right side has numbers 1-4 as well)

from left column to the right marching definition column:
1=2
2=4
3=1
4=3