A company advertises two car tire models. The number of thousands of miles that the standard model tires last has a mean \mu_S = 60μ
S
=60 and standard deviation \sigma_S = 5σ
S
=5. The number of miles that the extended life tires last has a mean \mu_E = 70μ
E
=70 and standard deviation \sigma_E = 7σ
E
=7. If mileages for both tires follow a normal distribution, what is the probability that a randomly selected standard model tire will get more mileage than a randomly selected extended life tire?

On a certain portion of an experiment, a statistical test result yielded a p-value of 0.18. what can you conclude? 2(0.18) = 0.36 < 0.5; the test is not statistically significant. if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 18% of the time, so the test is not statistically significant. if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 82% of the time, so the test is not statistically significant. 0.18 > 0.05; the test is statistically significant. p = 1 - 0.18 = 0.82 > 0.05; the test is statistically significant.

How american was colonial art? to what extent does it illustrate the development of a new society

Which allows college students to work part time jobs to pay for educational expenses