Last month, he sold 50 chickens and 30 ducks for \$550
$550dollar sign, 550. this month, he sold 44 chickens and 36 ducks for $532

Cost of one (chicken) =  $ 8

Cost of one (duck)  = $ 5

Explanation: heyy there :)

Let c be (chickens) and d be (ducks)

Given :  

50 �+ 30 � = $ 550

Dividing both sides by 10,

5 + 3 = 55 Eqn (1)

44 + 36 = $ 532

11 + 9 = 133 Eqn (2)

Multiply Eqn (1) by 3 to eliminate y term when subtraing Eqn (1) from (2).

Then a Eqn (1) becomes, 15 + 9 = 165 Eqn (3)

Subtracting Eqn (2) from (3),

(15 - 11) = (165 - 133)

4 = 32 or = $ 8.

Substituting value of in Eqn (1),

(5 * 8) + 3 = 55

3 = 55 - 40 = 15

= 15 / 3 = $ 5