Advanced Placement (AP), 23.06.2019 11:50 yungkxng57

Quickly! ill give you brainliest + free points the best approach to keeping your car in safe working order is to a. have a friend inspect it b. get a professional tune-up c. listen to the engine while it's running d. clean the interior and exterior once a month

Answers: 1

Show answers

Answers

Answer from: dajahp

the answer is b.

Explanation:

There is only one answer that makes sense. A professional tune up replaces old spark plugs, fills the vehicle with necessary fluids for proper engine function.

Answer from: liluzisquirt7378

B. get a professional tune-up

Explanation:

The best way in which you can make sure that your car is in a safe working order is to have it check by a professional. You should have your car inspected regularly by an expert mechanic to make sure that it is working properly and find possible issues before they become more serious. Doing this, can help to avoid a risky situation for driving a car that is not on the best condition.

The other options are not right because it is possible that a friend doesn't have the necessary knowledge to make sure that everything is working properly, the engine is not the only part of the car that can have a problem and cleaning the car has nothing to do with it working properly.

Answer from: Quest

Answer: the interval on which the curve is concave up is (-∞, -1/2)====== $\displaystyle y = \int_{0}^x \frac{1}{1 + t + t^2} \; dt$ we find the interval where this curve is concave up by finding the interval in which the 2nd derivative is positive.differentiate the curve equation with respect to x $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \end{aligned}$ let the function f denote be the anti-derivative of the inside expression, i.e. a function such that $(d/dx)f(x) = 1/(1 + t + t^2)$ .then use the fundamental theorem of calculus: $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \\& = \frac{d}{dx} \big[ f(x) - f(0) \big] & & \text{\footnotesize apply ftc} \\ & = \frac{d}{dx}f(x) - 0 \\ & = \frac{1}{x + x + x^2} & & \text{\footnotesize since $\frac{d}{dx}f(x) = \frac{1}{1 + x + x^2}$ } \end{aligned}$ differentiate again to get second derivative. we can use chain rule with 1/x as the outside function and 1 + x + x² as the inside function $\begin{aligned} \frac{d}{dx} \left( \frac{dy}{dx} \right) & = \frac{d}{dx}\left(\frac{1}{1 + x + x^2} \right) \\ \frac{d^2y}{dx^2} & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot \tfrac{d}{dx}(1 + x + x^2) \\ & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot (1 + 2x) \\ & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \end{aligned}$ find critical numbers of the second derivative. these numbers are where the 2nd deriv. is undefined or zero.where the 2nd derivative is zero: set (d²y/dx²) to equal 0 and solve for x $\begin{aligned} 0 & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \\ 0 & = -(1+2x) \\ -1 & = 2x \\ x & = -1/2 \end{aligned}$ where the 2nd derivative is undefined: if the denominator is equal to zero, the derivative will be undefeined. attempting to solve the equation 1 + x + x² = 0results in a discriminant of $b^2 - 4ac = 1^2 - 4(1)(1) = -3$ meaning that the equal 1 + x + x² = 0 has no real solutions and therefore will never equal zero.======our only critical number is x = -1/2.this forms two intervals to test the sign for: (-∞, -1/2) and (-1/2, ∞)test values into the 2nd derivative for (-∞, -1/2)if we try x = -1, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = -1} & = \frac{-(1+2(-1))}{\left(1+(-1)+(-1)^2\right)^2} \\ & = \frac{-(1-2)}{1} \\ & = 1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave up on (-∞, -1/2)test values into the 2nd derivative for (-1/2, ∞)if we try x = 0, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = 0} & = \frac{-(1+2(0))}{\left(1+(0)+(0)^2\right)^2} \\ & = \frac{-(1)}{1} \\ & = -1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave down on (-∞, -1/2).the interval on which the curve is concave up is (-∞, -1/2)

Answer from: Quest

a. ease it back slightly

Another question on Advanced Placement (AP)

Advanced Placement (AP), 23.06.2019 04:31

The us is not democratic (facts/data/information/reason to prove the us is undemocratic)

Answers: 2

Answer

Advanced Placement (AP), 23.06.2019 11:50

1. which of the following factors would cause demand-pull inflation? a. serious crop failure b. significant decrease in the supply of oil c. increase in the money supply d. increase in the cost of raw materials for firms e. reduction in imports allowed into the country

Answers: 3

Answer

Advanced Placement (AP), 25.06.2019 21:00

Identify one way in which the changes during the industrial revolution can be considered a political turning point in world history

Answers: 1

Answer

Advanced Placement (AP), 26.06.2019 12:00

20 pts i don't really get this xd1. what is the function in humans of the protein produced from that gene2. would you expect to find the same protein in other organisms? if so, which ones? 3. is it possible to find the same gene in two diff. kinds of organisms4. if you found the same gene in all organisms you test, what does this esuggest about the evolution of this gene in the history of life on earth? 5. does the use of dna sequences in the study of evolutionary relationships mean that other characteristics are unimportant in such studies? explain your answer. what am i supposed to do here

Answers: 1

Answer

You know the right answer?

Quickly! ill give you brainliest + free points the best approach to keeping your car in safe worki...

Questions